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Date: Fri, 7 Sep 2018 11:18:21 -0400
From: Rich Felker <dalias@...c.org>
To: musl@...ts.openwall.com
Cc: Steffen Nurpmeso <steffen@...oden.eu>
Subject: Re: Regex: behaviour of ? after () atom
On Fri, Sep 07, 2018 at 03:38:05PM +0200, Steffen Nurpmeso wrote:
> Hello.
>
> In perl this is
>
> $x="print 1 2";
> if($x =~ /^(:[[:space:]]+)?([^[:space:]]+)(.*)$/){
> print "<$0> -> <$1> <$2> <$3>\n"
> }
>
> and the result is
>
> </tmp/t.pl> -> <> <print> < 1 2>
>
> Now the same on AlpineLinux edge and musl-1.1.19-r10 with the MUA
> i maintain, which uses the normal regex stuff and calls it via
>
> echo eins=$3
> vput vexpr i regex "${3}" \
> '^(:[[:space:]]+)?([^[:space:]]+)(.*)$' \
> '<\$0> -> <\$1> <\$2> <\$3>'
> echo i=$i
>
> which in C code does
>
> if((reflrv = regcomp(&re, argv[2], reflrv))){
> ...
> goto jestr;
> }
> fprintf(stderr, "GOING for <%s> -> <%s> %u\n",
> argv[1],argv[2],n_NELEM(rema));
> reflrv = regexec(&re, argv[1], n_NELEM(rema), rema, 0);
>
> and overall prints
>
> eins=print 1 2
> GOING for <print 1 2> -> <^(:[[:space:]]+)?([^[:space:]]+)(.*)$> 17
> i=<print 1 2> -> <> <> <>
>
> It works correctly if i remove the ()? atom, so i thought i should
> report that.
What is the value of the flags argument you passed to regcomp?
Rich
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