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Date: Fri, 07 Sep 2018 15:38:05 +0200
From: Steffen Nurpmeso <steffen@...oden.eu>
To: musl@...ts.openwall.com
Subject: Regex: behaviour of ? after () atom
Hello.
In perl this is
$x="print 1 2";
if($x =~ /^(:[[:space:]]+)?([^[:space:]]+)(.*)$/){
print "<$0> -> <$1> <$2> <$3>\n"
}
and the result is
</tmp/t.pl> -> <> <print> < 1 2>
Now the same on AlpineLinux edge and musl-1.1.19-r10 with the MUA
i maintain, which uses the normal regex stuff and calls it via
echo eins=$3
vput vexpr i regex "${3}" \
'^(:[[:space:]]+)?([^[:space:]]+)(.*)$' \
'<\$0> -> <\$1> <\$2> <\$3>'
echo i=$i
which in C code does
if((reflrv = regcomp(&re, argv[2], reflrv))){
...
goto jestr;
}
fprintf(stderr, "GOING for <%s> -> <%s> %u\n",
argv[1],argv[2],n_NELEM(rema));
reflrv = regexec(&re, argv[1], n_NELEM(rema), rema, 0);
and overall prints
eins=print 1 2
GOING for <print 1 2> -> <^(:[[:space:]]+)?([^[:space:]]+)(.*)$> 17
i=<print 1 2> -> <> <> <>
It works correctly if i remove the ()? atom, so i thought i should
report that.
Ciao,
--steffen
|
|Der Kragenbaer, The moon bear,
|der holt sich munter he cheerfully and one by one
|einen nach dem anderen runter wa.ks himself off
|(By Robert Gernhardt)
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