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Date: Sun, 14 Aug 2011 12:46:14 +0200
From: magnum <>
Subject: Re: Re: md5(md5($p).$s) - VB

On 2011-08-14 05:55, Donovan wrote:
> all try's doing without success ;
> user md5_gen(7)33be23d72f2650dd0d049cf1e274fe24$M's
> md5_gen(7)33be23d72f2650dd0d049cf1e274fe24$M's
> Can some one try please ?

$ cat donovan.txt
user md5_gen(7)33be23d72f2650dd0d049cf1e274fe24$M's

$ ./john donovan.txt -fie=" "
using field sep char ' ' (0x20)
Loaded 1 password hash ( md5_gen(7): md5(md5($p).$s)  (vBulletin)  [SSE2 
16x4x2 (intr)])

I just found this odd behaviour when testing: It claims I don't have the 
format unless I give a field separator.

$ ./john -test -fo:"md5_gen(7)"
Unknown ciphertext format name requested

$ ./john -test -fo:"md5_gen(7)" -fie=" "
using field sep char ' ' (0x20)
Benchmarking:  md5_gen(7): md5(md5($p).$s)  (vBulletin)  [SSE2 16x4x2 
(intr)]... DONE


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