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Date: Wed, 1 Oct 2014 20:13:56 +0200
From: Szabolcs Nagy <>
Subject: Re: converting gcc from glibc to musl

* stephen Turner <> [2014-10-01 13:54:25 -0400]:
> On Wed, Oct 1, 2014 at 12:10 PM, Szabolcs Nagy <> wrote:
> > - can gcc compile a minimal program (empty main)?
> >
> I can compile the following program sucessfully to a.out but cannot run it.
> # include <stdio.h>
> main()
> {
> printf("hello world\n");
> }
> gcc test.c && chmod +x a.out && ./a.out
> > - where does gcc/ld fail, how were they invoked (gcc -v)?
> configure:2078: loading cache /dev/null

i meant running

 gcc -v test.c

not the configure thing

(so we know if the compiler works at all before
starting to debug the configure script)

> - in the executable is the loader properly set up (readelf)?

check if the machine type/abi is ok:

 readelf -h a.out

check if the musl loader is set up as expected:

 readelf -l a.out

(in case of dynamic linking the interpreter should be
/lib/ otherwise there should be no

> - check if the loader/libc at the right path

ls -l /lib/ld-musl-*

> - can you run the executable with the loader explicitly?


/lib/ ./a.out

> > - strace the executable, where does it fail?

strace ./a.out

> I dont know how to do what your asking here is there a site i can ref on
> these troubleshooting steps?

if you are not experienced with toolchains i'd try
alpine or sabotage linux first
you might be able to customize them to your liking

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