
Date: Thu, 15 Mar 2012 19:22:41 +0100 From: Szabolcs Nagy <nsz@...t70.net> To: musl@...ts.openwall.com Subject: Re: correctly rounded sqrt * Pascal Cuoq <pascal.cuoq@...il.com> [20120315 19:14:09 +0100]: > >> if (signexp >= 0x7fff) is probably a better check > > > > Haha, this is the second time I stupidly forget sqrt(x) is > > nonnegative... :) Fixing it.. > > I apologize if this is not relevant ???I admit I followed the discussion with only half my attention??? but note that sqrt(0.) is 0., so the sign bit may be set in both argument and result of sqrt(). yes, that's handled correctly we were talking only about the 'hard to round case' (long double square root significand ends in ..xxx10000000000) dalias: meanwhile i realized that a double nan cannot end in 0x400 when converted to long double so i was wrong about the nan check, it's not needed sorry (maybe it makes sense to add a small comment to that sqrt.s because it's not trivial for newcommers)
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