Date: Sun, 10 Jan 2016 14:46:56 +0100 From: Patrick Proniewski <patpro@...pro.net> To: john-users@...ts.openwall.com Subject: meaning of p/s, c/s and C/s Hello, I've read the FAQ about the meaning of the status line, but I think I need a bit more info. I'm running a john session with --fork=4 ans --mask=[a-zA-Z0-9][a-zA-Z0-9][a-zA-Z0-9][a-zA-Z0-9][a-zA-Z0-9][a-zA-Z0-9][a-zA-Z0-9][a-zA-Z0-9] that yields to this kind of status lines: 1 0g 0:00:02:16 (8) 0g/s 933.4p/s 3819Kc/s 29306KC/s yoHaaaaa..BqHaaaaa 2 0g 0:00:02:16 (8) 0g/s 937.1p/s 3835Kc/s 29425KC/s OwHaaaFp..RyHaaaFp 3 0g 0:00:02:16 (8) 0g/s 935.3p/s 3829Kc/s 29386KC/s GsHaaaaF..JuHaaaaF 4 0g 0:00:02:16 (8) 0g/s 960.6p/s 3933Kc/s 30182KC/s qmIaaaFU..toIaaaFU I'm targeting 31394 passwords (traditional crypt(3) [DES 128/128 AVX-16]), with 4092 different salts. So if I get it correctly: - john is testing about 940 passwords per second for each forked process. - john is computing about 3850000 hashes per second for each forked process, it should be equal to (number of salts)*(p/s): non-salted hashes should give same number for p/s and c/s. - many passwords are sharing the same salt, so every hash computed can be tested against ~ 31394/4092 passwords. C/s is then equal to (p/s)*(remaining number of passwords), or (c/s)*(number of passwords)/(number of salts). And, according to the poor rate of ~940 passwords per second, and the mask covering a 62^8 space, I'll be finished in 1871 years. is that correct? thanks, pat
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