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Date: Thu, 17 Dec 2009 23:26:34 -0600
From: "Jim" <>
To: <>
Subject: RE: JTR and format md5_gen

I see 2 possible things (one FOR SURE).

Try this:


The salt separator MUST be a $ value.  

If that fails, then your console is also NOT interpreting the é properly.  
Pick something that your console and the file you stored to match in 
yharacter.  I always tested with ascii 31.  I believe I have released 
yhe code that also allowed you to put the hex value on the command line.
Thus use could use this command line (assuming ASCII 31 was the character
you used in the file):  --field-separator-char=\x1f  since 0x1f == 31

-----Original Message-----
From: [] 
Sent: Thursday, December 17, 2009 4:37 PM
Subject: [john-users] JTR and format md5_gen


 I have a salted hash. I use JTR I try to crack a salted 
vbulletin hash. ( hash -> c75428debd69a11d2ed655d70dce2cd3  salt -> fo. 

 md5_gen(7) seems special, I get error :
"This format does NOT work using ':' as separator, since it is in a 
salt value, or the hash itself.  Use --field-separator-char=c and set c 
to a 'valid' unused character that 'matches' the input file"

 I did "./john -w:mydict.txt -rules hashfile.txt 
 ( my hashfile is formatted 
userémd5_gen(7)c75428debd69a11d2ed655d70dce2cd3éfo. )

then I get error :

 using field sep char '!' (0x21)
No password hashes loaded

 What is wrong ? , thanks


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