Date: Fri, 16 Jun 2006 19:28:40 +0000 (UTC) From: Phantom <phantom_otw@...oo.com> To: john-users@...ts.openwall.com Subject: Re: Inverted chatsets? Solar Designer <solar@...> writes: > So you must be talking about "inverting" character frequencies, not the > character set. That would mean that we treat the characters and > character combinations that were most commonly seen in our sample > passwords as the least likely ones, and instead treat the characters and > character combinations that were never seen as the most likely ones. In > other words, we would sort of start our search from the "end" of the > list of candidate passwords that "incremental mode" normally generates. Yes, that is what I ment. Sorry for not beeing more clear > Of course, chances are that we won't get any passwords cracked in any > reasonable amount of time in this way. Well, I still say it would be worth testing :) Since there must be some passwords, where doing it "backwards" would be faster than the normal way...? > On the other hand, if you, for example, have run digits.chr and then > proceed to run all.chr, you actually want to exclude all-numeric > passwords from those produced by -i=all. Right now, the only way to do > that is with an external filter(). But you might as well choose to not > do it since all-numeric passwords correspond to a small portion of the > password space, whereas filtering has a certain processing cost for all > candidate passwords (including those that contain non-digits). This > example also serves to illustrate one reason why I suggest that people > go for all.chr (or lanman.chr) right away, without bothering with the > more restrictive charsets. yeah, I see what you mean.. Then, it might be beneficial to be able to start -i:all from a certain point, further on in the frequency "tables" - something like skip the first 10 mill most likely combination and start from there instead? I find it hard to figure out how the .rec files are built and how, if possible, one could edit a .reito make it jump past some combinations and start from somewhere else... Regards
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