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Date: Wed, 25 Jun 2014 00:58:41 +0200
From: magnum <john.magnum@...hmail.com>
To: john-dev@...ts.openwall.com
Subject: Re: split vs prepare
On 2014-06-25 00:26, magnum wrote:
> Here's the order things happen (I think) when you load a hash for cracking:
>
> "input line" -> prepare() -> valid() -> split() -> "source"
>
> This "source" is what will be written to the pot file in case we crack
> the hash - and binary() and salt() will be called with "source". But I'm
> not quite sure how cracked hashes are found when loading a file. What is
> really needed to recognize a .pot line which does not resemble an input
> line?
OK, an obvious difference when loading a *pot* file line is we never
call prepare().
I'm trying to wrap my head around this. Let's say we load this line from
an input file:
user:UPPERCASE_HASH
and we have this line in the pot file:
lowercase_hash:password
The format will load the "input line" -> prepare() -> valid() -> split()
-> "source" as above. Source is now "TAG$lowercase_hash". Then -> binary().
When comparing a pot file line, it will go:
"input line" -> valid() -> split() -> binary() -> binary_hash()
Hmmm but if we are comparing binaries, how come an untagged hash was not
recognized when I tried doing tagging in prepare()?!
I'm confused.
magnum
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