john-users - Re: duplicate 2 latest digits

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Date: Mon, 19 Apr 2010 03:22:54 +0400
From: Solar Designer <solar@...nwall.com>
To: john-users@...ts.openwall.com
Subject: Re: duplicate 2 latest digits

On Sun, Apr 18, 2010 at 10:37:49PM +0200, websiteaccess@...il.com wrote:
>  I would like duplicate 2 times the last 2 digits .
> wordlist : john
> 
>  john + (from 00 to 99)
>  john -> john000000 to john 999999

Here's the ruleset line to do what you need:

Az"[0-9][0-9]\1\2\1\2"

It produces:

john000000
john010101
john020202
...
john090909
john101010
john111111
...
john979797
john989898
john999999
words: 100  time: 0:00:00:00 100%  w/s: 10000  current: john999999

You may also prefix the line with a length check such that you do not
try adding the 6-character strings to words that are already too long.
For example, to ensure there's room for at least two characters:

<- Az"[0-9][0-9]\1\2\1\2"

or to ensure there's room for at least three characters (such that the
resulting candidate passwords will be different from those produced by
an append-two-digits ruleset line, which is probably also present):

va*2 <a Az"[0-9][0-9]\1\2\1\2"

or to ensure there's room for all 6 characters:

va*5 <a Az"[0-9][0-9]\1\2\1\2"

or just restrict this to short words (irrespective of what the target
hash type's length limit is):

<7 Az"[0-9][0-9]\1\2\1\2"

or combine both kinds of restrictions:

<7 va*2 <a Az"[0-9][0-9]\1\2\1\2"

This kind of complexity may be beneficial in "universal" rulesets that
are meant to be near-optimal for all hash types.

Alexander